Answer:
5
Step-by-step explanation:
25 -5 - 5 -5 -5 -5 hope this helps
Answer:
a) The margin of error for a 90% confidence interval when n = 14 is 18.93.
b) The margin of error for a 90% confidence interval when n=28 is 12.88.
c) The margin of error for a 90% confidence interval when n = 45 is 10.02.
Step-by-step explanation:
The t-distribution is used to solve this question:
a) n = 14
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 14 - 1 = 13
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of . So we have T = 1.7709
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The margin of error for a 90% confidence interval when n = 14 is 18.93.
b) n = 28
27 df, T = 1.7033
The margin of error for a 90% confidence interval when n=28 is 12.88.
c) The margin of error for a 90% confidence interval when n = 45 is
44 df, T = 1.6802
The margin of error for a 90% confidence interval when n = 45 is 10.02.
By finding the least common denominator (LCD), and then go from there.
Answer: $9.86
Step-by-step explanation:
$11.60 ⋅ 8.5 = $98.60
$98.60 / 10 = $9.86
Answer:
h = 5
Step-by-step explanation: