A rectangle has an area of 120 square cm. Its length and width are whole numbers. List the possible dimensions of the rectangle.
Which possibility gives the smallest perimeter?
1 answer:
Answer: kindly check explanation
Step-by-step explanation:
Given that:
Area of rectangle = 120 cm²
Assume ; Length and width are whole numbers
Possible dimension of the rectangle will be :
Area of a rectangle = Length × width
Area = 120cm²
Possible dimensions :
80cm by 1 cm
40cm by 2cm
20cm by 4cm
10cm by 8cm
5cm by 16cm
Possibility which gives the smallest perimeter :
Dimension = 10cm by 8cm
Perimeter of Rectangle = 2(length + width)
Perimeter of Rectangle :
= 2(10 + 8)cm
= 2(18)cm
= 36cm
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Answer:
48 degrees
Step-by-step explanation:
7X-1+12x+48=180
19x+47=180
19x=133
x=7
7(7)-1=A
49-1=A
48=A
A is 48 degrees
Answer:
x < - 4
Step-by-step explanation:
Given
2x - 2 > 4x + 6 ( subtract 2x from both sides )
- 2 > 2x + 6 ( subtract 6 from both sides )
- 8 > 2x ( divide both sides by 2 )
- 4 > x , thus
x < - 4
For this problem you need to put the x values in for x in the equation. For example, put -10 in for x and calculate y, which is g(x)
Answer:
(8,5)
Step-by-step explanation:
x=8
5*8-2y=30
40-2y=30 . subtract 40 from both sides
-2y=-10 . divide both sides by-2
y=5
