The work done is the product between the intensity of the force applied F, the amount of the displacement d of the book and the cosine of the angle
between the direction of the force and the direction of the displacement:
In our problem, the student is lifting the book, so he is applying a force directed upward, and the book is moving upward, so F and d are parallel and therefore the angle is zero, so
Therefore, the work done is
Answer:
If an object moves along a straight line, the distance traveled can be represented by a distance-time graph. In a distance-time graph, the gradient of the line is equal to the speed of the object. The greater the gradient (and the steeper the line) the faster the object is moving.
Explanation:
Answer:
The charge carried by the droplet is
Explanation:
Given that,
Distance =8.4 cm
Time = 0.250 s
Suppose tiny droplets of oil acquire a small negative charge while dropping through a vacuum in an experiment. An electric field of magnitude points straight down and if the mass of the droplet is
We need to calculate the acceleration
Using equation of motion
Put the value into the formula
We need to calculate the charge carried by the droplet
Using formula of electric filed
Put the value into the formula
Hence, The charge carried by the droplet is