PLEASE HELP ASAP! BRAINLIEST!<br>
Is this a function???<br>
{(0,2),(1,4),(2,8),(3,16),(4,32),(5,64)}
Svetradugi [14.3K]
Answer:
yes
Step-by-step explanation:
it passes the verticle line test
the x-values only goto one y-value
Answer:
<u>D) (f o g)(x) = 10x² - 60x + 93</u>
Step-by-step explanation:
f(x) = 10x² + 3
g(x) = x - 3
⇒ (f o g)(x)
⇒ f(x - 3)
⇒ f(x - 3) = 10(x - 3)² + 3
⇒ f(x - 3) = 10(x² - 6x + 9) + 3
⇒ f(x - 3) = 10x² - 60x + 90 + 3
⇒ <u>(f o g)(x) = 10x² - 60x + 93</u>
The fraction of a circle represented by the shaded region is:
S '/ S = ((8/5) * pi * r) / (2 * pi * r)
Rewriting we have:
S '/ S = ((8/5)) / (2)
S '/ S = 8/10
S '/ S = 4/5
Then, we can make the following rule of three:
(64/5) pi -------> 4/5
x ----------------> 1
Clearing x we have:
x = ((1) / (4/5)) * ((64/5) pi)
Rewriting:
x = (5/4) * ((64/5) pi)
x = (5/4) * ((64/5) pi)
x = 50.24
Answer:
The area of the complete circle is:
x = 50.24
Answer:
Where's the picture?
Step-by-step explanation:
Can't see it.
3x -y ⩾ 6
3x - 6 ⩾ y
now, with inequalities, what we do is, we graph the line of 3x - 6 = y, and then we shade the "true region".
if we pick a point on say hmmm (4, 0), namely x = 4 and y = 0, we can plug that in the inequality and see what we get,
3(4) - 0 ⩾ 6
12 - 0 ⩾ 6
12 ⩾ 6
is 12 really greater or equals to 6? well yes, therefore, the point (4, 0) lies on the "true region", since it's true, 12 is indeed ⩾ 6, so, where that point is, we shade.
now, the ⩾ means equals to or greater, and therefore, since the values could also equal the boundary points, the line is a solid line, because it includes the line itself, as well as the shading.
check the picture below.