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2 years ago

What is the solution to log Subscript 3 Baseline (x + 12) = log Subscript 3 Baseline (5 x)

Mathematics

1 answer:

jonny [76]2 years ago

6 0

I hope this helps you

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Evaluate the following expression. 5^-3

Ulleksa [173]

5^-3 is 1/125

The negative in the exponent makes it so there is a 1 over the problem if there was no negative. When you have a negative in the exponent, the answer will be the reciprocal (opposite) of the question with no negative.
For example,

9^2 = 81

9^-2 = 1/81

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2 years ago

1/2 of 3 + 3/4 of 3 +1/2 of 2=

Vedmedyk [2.9K]

=3/2+ 9/4+ 2/2
=1.5+ 2.25+ 1
=4.75

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3 years ago

Find the number which exceeds 17319 by 1279

Andrei [34K]

Answer:

18598

Step-by-step explanation:

just add

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2 years ago

Pleasee help me I just wanna go to sleep already :c

Lunna [17]

Answer: 17 is A and 18 is B

Used a calculator to add them all up! Get some sleep hope this helps.

17) 2(3x8)+2(3x6)+2(6x8) = 180

18) 4(9x2)+2(9x9) = 234

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2 years ago

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$ </em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

<u>Formula for the coordinate of mid-point</u> : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be: $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be: $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

Thus, the endpoint coordinates for the mid-segment of $\triangle BCD$ that is parallel to $BC$ are $(-2,-1)$ and $(1,0)$

4 0

2 years ago

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