H(x), or the range of this function, must be y >= 0, as you can never get a negative when square rooting any number.
For the domain, x cannot exceed -2 or 2, as this would mean we'd be finding the square root of a negative number, which can't happen without getting in to imaginary numbers. Thus, the domain must be -2 <= x <= 2.
60/48
Both can be reduced by 12 to 5/4
So you can have 12 groups with 5 6th graders and 4 7th graders
Answer:
You cannot simplify this problem down anymore; it is at its simplest form.
Step-by-step explanation:
You cannot add together x^4 and x^2 due to the simple fact that they do not share similar exponents.
For example you could add together x^4 and x^4 to get 2x^4. But you cannot add x^4 and x^2.
The equation that models the number of funnel cakes and Oreos he can buy is 3.50x + 2.0y = 42
Data given;
- Cost of Oreos = $2.00
- The total amount spent = $42.00
<h3>What is the Equation</h3>
To solve this problem, we just need to write out an equation to show how he can spend $42.00 in the fair on Oreos and Cakes.
Let x represent the cakes
Let y represent the Oreos
The equation is thus;
The equation that shows the number of Cakes and Oreos can by is
3.50x + 2.0y = 42
Learn more about equation here;
brainly.com/question/13729904
Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.