Answer:
N and P
Step-by-step explanation:
N and P grab a like and move the ends in a circle around each letter if they look symmetrical at any point that letter has a line of symmetry.
Answer:
No, it is not a right triangle.
Step-by-step explanation:
The simplest way to determine is testing out the numbers with Pythagorian theorem.
If it complies with the theorem, it is a right triangle.
let's assume c = 28, b = 21, and a = 20
the longest side is the hypotenuse so side c (28 in) will be the hypotenuse.
According to the Pythagorian theorem, the square of the length of hypotenuse must equal to the sum of squares of other two sides.
check:
c^2 = 28^2 = 784
a^2 + b^2 = 21^2 + 20^2 = 841
because c^2 is not equal to a^2 + b^2, the triangle is not a right triangle.
X=1, and 3/8 it is a mixed number.
For this case we have the following expression:
(1 / x + 2) + (1 / x + 3) + (1 / X ^ 2 + 5 + 6)
Rewriting we have:
(1 / x + 2) + (1 / x + 3) + (1 / ((x + 2) * (x + 3)))
By doing common factor we have:
(1 / ((x + 2) * (x + 3))) * (x + 3 + x + 2 + 1)
Rewriting:
(1 / ((x + 2) * (x + 3))) * (2x + 6)
The sum is:
((2x + 6) / ((x + 2) * (x + 3)))
Answer:
((2x + 6) / ((x + 2) * (x + 3)))
Emma completed the problem correctly i believe