Answer:
2nd graph
Step-by-step explanation:
Given
f(x) = x² + 3x - 4
To find the zeros let f(x) = 0 , that is
x² + 3x - 4 = 0 ← in standard form
(x + 4)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 4 = 0 ⇒ x = - 4
x - 1 = 0 ⇒ x = 1
The only graph with zeros at x = - 4 and x = 1 is the 2nd graph
Answer:
f(x) = x² - 81 = ( x+ 9)(x - 9) Difference of two squares
g(x) = x+9/x-9
g(x) . f(x) = x + 9/ x - 9 × (x+9)(x - 9)
= ( x + 9)(x +9)
= ( x + 9)²
= x² + 18x + 81
Hope this helps.
1. 32 cents
2.im not sure
Answer:
x
Step-by-step explanation:
Y=x^2-6x+14
=x^2-6x+9-9+14
x^2-3x-3x+9 +5
x(x-3)-3(x-3)+5
(x-3)^2+5
here h=3
minimum value would be 5