Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.
Answer:
5/7
Step-by-step explanation:
6/7-1/7=5/7
Answer:
(13 x + 6) (x - 2)
Step-by-step explanation:
Factor the following:
13 x^2 - 20 x - 12
Factor the quadratic 13 x^2 - 20 x - 12. The coefficient of x^2 is 13 and the constant term is -12. The product of 13 and -12 is -156. The factors of -156 which sum to -20 are 6 and -26. So 13 x^2 - 20 x - 12 = 13 x^2 - 26 x + 6 x - 12 = x (13 x + 6) - 2 (13 x + 6):
x (13 x + 6) - 2 (13 x + 6)
Factor 13 x + 6 from x (13 x + 6) - 2 (13 x + 6):
Answer: (13 x + 6) (x - 2)
Answer:Please include images of the graphs!
The mean is 10.
To find the mean you add up all the numbers and divide by how many sets of numbers there were.
8+10+11+8+13=50
50/5=10.