Question

Adam and Brian are standing some distance apart on the side of a building 50 m tall .from where Adam stands ,the angle of elevation of the top of the building is 30' from where Brian stands , the angle is 60 what is the distance x between Adam and Brian to the nearest tenth of a meter

Answer 1

Tanα=h/d

d=h/tanα, h is 50m for both calculations...

a=50/tan30

b=50/(tan60)

The distance,d,  between them is

d=a-b

d=50/tan30-50/tan60

d≈57.7m