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2 years ago

I need help with the problem

1 answer:

4 0

The length is 15 metres,the width is 9 m,and the area is 135 m

Hope this will help u..

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igomit [66]

Answer:

$y=\cot \theta$ and $y=\csc \theta$

Step-by-step explanation:

Note that if $\cos \theta=1,$ then $\sin \theta=0.$

Functions $y=\cos \theta,\ \ y=\sin \theta$ do not have vertical asymptotes at all.

Vertical asymptotes have functions $y=\tan \theta,\ \ y=\cot \theta,\ \ y=\sec \theta,\ \ y=\csc \theta.$

Functions $y=\tan \theta$ and $y=\sec \theta$ have the same vertical asymptotes (when $\cos \theta =0$ ).

Functions $y=\cot \theta$ and $y=\csc \theta$ have the same vertical asymptotes (when $\sin \theta =0$ ). See attached diagram

3 0

2 years ago

sattari [20]

Answer:

The middle number would be (14+15)/2 = 14.5

How I found that is I did (14+15)/2.

pls mark as branliest

3 0

2 years ago

Kryger [21]

I don't know kid I'm busy right now

6 0

2 years ago

DaniilM [7]

Then why shane shahs. A

3 0

2 years ago

Ilya [14]

2 inches is equal to 5.08 centimeters

Hope this helps you. :-)

5 0

2 years ago