Answer:
D;the last answer
Step-by-step explanation:
The more negative a fraction or decimal, the lower that actual value.
Therefore since -1 1/5 is the lowest it should go first, and D is the only answer like this! Hope this helps ^^
It’s not a function because the domain (the X) is repeating...
X cannot repeat if you want it to be a function
The interval where the function is increasing is (3, ∞)
<h3>Interval of a function</h3>
Given the rational function shown below
g(x) = ∛x-3
For the function to be a positive function, the value in the square root must be positive such that;
x - 3 = 0
Add 3 to both sides
x = 0 + 3
x = 3
Hence the interval where the function is increasing is (3, ∞)
Learn more on increasing function here: brainly.com/question/1503051
#SPJ1
Answer:
dam this been up for a long time
Step-by-step explanation:
its just too hard sorry man
Answer:
Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.
<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that 
. Thus, A↔A.
<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that 
. In this equality we can perform a right multiplication by 
and obtain 
. Then, in the obtained equality we perform a left multiplication by P and get 
. If we write 
and 
we have 
. Thus, B↔A.
<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have and from B↔C we have 
. Now, if we substitute the last equality into the first one we get
.
Recall that if P and Q are invertible, then QP is invertible and 
. So, if we denote R=QP we obtained that
. Hence, A↔C.
Therefore, the relation is an <em>equivalence relation</em>.
