In this situation, you have:
The mode is 79 (that’s the most common number).
The median is 78.5 (the middle value or the average of the two middle values, since there is an even number of test scores).
The mean is less than both of those, as it was brought down by the few scores of 49.
The means the mean will be less than median.
Answer: C
Answer:
The ratio of the difference of the two means to Sidney's mean absolute deviation = = 1.2195
Step-by-step explanation:
P.S - The exact question is -
Given - The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below.
Sidney’s Grades Phil’s Grades
Mean 82 78
Mean Absolute Deviation 3.28 3.96
To find - Which expression represents the ratio of the difference of the two means to Sidney’s mean absolute deviation?
Proof -
Given that Mean of Sidney Grades = 82
Mean of Phil's Grades = 78
So,
The difference of two means = 82 - 78 = 4
Also,
Given, Mean Absolute Deviation of Sydney = 3.28
Now,
The ratio of the difference of the two means to Sidney's mean absolute deviation = = 1.2195
Answer:
mans latvietis nav lielisks, bet spordai būtu 18 āboli
jūs sadalītu 28 ar 2, tad jums būtu 14 abiem, pēc tam paņemiet 4 ābolus no aivaram un atdodiet šos četrus sportaai
Step-by-step explanation:
Sorry is this some sort of equation I’m confused