Question

AD= 36 cm. Points C, B∈AD, such that AB:BC:CD=2:3:4. Find the distance of midpoints of the segments AB and CD.

Answer 1

Answer:

The distance of the midpoints of AB and CD is 24 cm

Step-by-step explanation:

The given information are;

The length of AD = 36 cm.

C and B are points on AD

The ratio of AB:BC:CD 2:3:4

The distance of the midpoints of segments AB and CD required

Therefore, we have the following proportion of the total length, 36

Segment AB = 2/(2 + 3 + 4) = 2/9×36 = 8 cm

Segment BC = 3/(2 + 3 + 4) = 3/9×36 = 12 cm

Segment CD = 4/(2 + 3 + 4) = 4/9×36 = 16 cm

The x-coordinate of the midpoint of segment AB = 4 cm

The x-coordinate of the midpoint of segment CD = 8 + 12 + 16/2 = 28 cm

Which gives;

The distance of midpoint of segment AB from A = 4 cm

The distance of midpoint of segment CD  from A = 28 cm

And the distance of the midpoints of AB and CD = 24 - 4 = 24 cm.