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2 years ago

What is 6 persent of 3600

Mathematics

2 answers:

FrozenT [24]2 years ago

5 0

216 is the answer I got for 6% of 3600

Cerrena [4.2K]2 years ago

4 0

6 percent is 6% or 0.06.
So it'd be 0.06×3600=216

6 percent of 3600 is 216

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15% of 60 is what percent of 180?

aivan3 [116]

Okay so uh i think it’s this: 15% of 60=0.15* 60=9
9 is what percent of 180 i think..?
9/180=1/20=5/100=5%

7 0

2 years ago

Read 2 more answers

What is the factorization of 729^15+1000?

igomit [66]

Answer:

The factorization of $729x^{15} +1000$ is $(9x^{5} +10)(81x^{10} -90x^{5} +100)$

Step-by-step explanation:

This is a case of factorization by sum and difference of cubes, this type of factorization applies only in binomials of the form $(a^{3} +b^{3} )$ or $(a^{3} -b^{3})$ . It is easy to recognize because the coefficients of the terms are perfect cube numbers (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of $729x^{15} +1000$ by using the sum and difference of cubes factorization.

1.) We calculate the cubic root of each term in the equation $729x^{15} +1000$ , and the exponent of the letter x is divided by 3.

$\sqrt[3]{729x^{15}} =9x^{5}$

$1000=10^{3}$ then $\sqrt[3]{10^{3}} =10$

So, we got that

$729x^{15} +1000=(9x^{5})^{3} + (10)^{3}$ which has the form of $(a^{3} +b^{3} )$ which means is a sum of cubes.

Sum of cubes

$(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})$

with $a= 9x^{5}$ y $b=10$

2.) Solving the sum of cubes.

$(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )$

$(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)$

8 0

2 years ago

The variable z is inversely proportional to x. When x is 16, z has the value 0.875. What is the value of z when x= 21?

ziro4ka [17]

For $z$ and $x$ to be inversely proportional, there must be some constant $k$ such that

$zx=k$

Given that $z=0.875$ when $x=16$ , it follows that

$0.875\cdot16=k\implies k=14$

Then when $x=21$ , we have

$21z=14\implies z=\dfrac{14}{21}=\approx0.667$

8 0

2 years ago

Twice the difference of a number and 2 is at most -27

igor_vitrenko [27]

<h2>Explanation:</h2><h2 />

When we say "a is at most b" we mean that "a is less than or equal to b" or "a is not greater than b". So let's solve this problem as follows:

Step 1. Twice the difference of a number and 2

Let's call that unknown number as n. Then, twice the difference of a number and 2 is:

$2(n-2)$

Step 2. Twice the difference of a number and 2 is at most -27

$2(n-2)\leq -27$

_________________________________________

So the mathematical form of the statement twice the difference of a number and 2 is at most -27 is:

$\boxed{2(n-2)\leq -27}$

5 0

2 years ago

(9x+2)(4x^2+35x-9)=0

pychu [463]

$(9x+2)*(4x^2+35x-9)=0$

we can make this...

$9x+2=0$

and

$4x^2+35x-9=0$

then...

$9x+2=0$

$\boxed{x=-\frac{2}{9}}$

$4x^2+35x-9=0$

$x=\frac{-b\pm\sqrt{b^2-4*a*c}}{2*a}$

$x=\frac{-35\pm\sqrt{35^2-4*4*(-9)}}{2*4}$

$x=\frac{-35\pm\sqrt{1369}}{8}$

$x=\frac{-35\pm37}{8}$

$x_1=\frac{-35+37}{8}=\frac{1}{4}$

$x_2=\frac{-35-37}{8}=-9$

$\boxed{\boxed{S=\{\frac{1}{4},-\frac{2}{9},-9\}}}$

I'm sure about my answer, don't matter the order...

4 0

2 years ago

Read 2 more answers