A 1451 kg car is traveling at 48.0 km/h. Compared to 48.0 km/h, what would be the fraction of energy the car would have if it we re traveling at 24.0 km/h.
2 answers:
Ke = (1/2)(m)(v^2) Ke = (1/2)(1451kg)(48^2) Ke = 1,671,552 joules Ke = (1/2)(1451)(24^2) Ke = 417,888 1/4th the energy
We know, kinetic energy is directly proportional to the square of velocity, So, if kinetic energy is halved it's velocity will reduce to its 1/4th valueIn short, Your Answer would be 1/4 Hope this helps!
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