Answer:
The final volume of the gas is 0.752 L.
Explanation:
Initial pressure of the gas =
Initial volume of the gas =
Initial temperature of the gas =
Final pressure of the gas =
Final volume of the gas =
Final temperature of the gas =
Number of moles of gases are constant
Using an ideal gas equation :
P1 * V1 ÷ T1 = P2 * V2 ÷ T2
45 * 1.20 ÷ 314 = 96 * V2 ÷ 420
30,144 * V2 = 22,680
V2 = 22,680 ÷ 30,144
The new volume is approximately 0.75 liter.
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The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.
D. It gives the same results when experiments are repeated
63.6 dm³
Volume of gas= no. of moles ×24dm³
Thus, volume of N₂O
= 2.65 × 24
= 63.6 dm³