ax² + bx + c = 0
x = (-b ± √(b² - 4ac))/2a
First, rewrite the first equation so that the first coefficient is 1. Divide everything by a.
(ax² + bx + c = 0)/a =
x² + (b/a)x + (c/a) = 0
Isolate (c/a) by subtracting (c/a) from both sides
x² + (b/a)x + (c/a) (-(c/a) = 0 (- (c/a)
x² + (b/a)x = 0 - (c/a)
Add spaces
x² + (b/a)x = -c/a
Take 1/2 of the middle term's coefficient and square it. Remember that what you add to one side, you add to the other.
x² + (b/a)x + (b/2a)² = -c/a + (b/2a)²
Simplify the left side of the equation.
x² + (b/a)x + (b/2a)² = (x + (b/2a))²
(x + b/2a))² = ((b²/4a²) - (4ac/4a²)) -> ((b² - 4ac)/(4a²))
Take the square root of both sides of the equation
√(x + b/2a))² = √((b²/4a²) - (4ac/4a²))
x + b/(2a) = (±√(b² - 4ac)/2a
Simplify. Isolate the x.
x = -(b/2a) ± (∛b² - 4ac)/2a = (-b ± √(b² - 4ac))/2a
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4x+7 = x+10 parallel sides have to be equal in a parallelogram
subtract x
3x +7 = 10
subtract 7 from each side
3x =3
divide by 3
x =1
The answer is 140, you just add them up and it goes by 2.
The most appropriate statement is the interquartile range for the Wolverines, 30 is less than the IQR for the panthers, 40.
<h3>What is the correct statement?</h3>
The box plot is used to show the distribution of data. The box plot can be used to determine the range, interquartile range and median of the data set.
The range is the difference between the two ends of the whiskers.
Range for the Wolverines = 96 - 35 = 61
Range for the Panthers = 107 - 33 = 74
The interquartile range is the difference between the first and third lines on the box
IQR for the Wolverines = 85 - 55 = 30
Range for the Panthers = 90 - 50 = 40
To learn more about box plots, please check: brainly.com/question/1523909
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Answer:
0
Step-by-step explanation:
product is another word for +
decreased is another word for -
____________________________
(7 + 8) - x
so
(7+8) - 15
15 - 15
= 0
