How do you solve -8k=-5k+9

2 answers:

7 0

You add +5k to both sides to eliminate-5k, leaving you with -3k=9 { since you added 5k to both sides } . then you divide both -3k on both sides { to isolate k }, leaving you with k = -3 as your answer.

Zolol [24]3 years ago

5 0

Answer:

k = -3

Step-by-step explanation:

This one is quite easy once you know how to achive this:

What you want to to is first add 5k to both sides

-8k + 5k = -5k + 5k + 9

This eliminates the 5k leaving

-3k = 9

And since you can't have a negative exponent, times both sides by -1

-3k x -1 = 9 x -1

3k = -9

Now divide both sides by 3 to get the answer

3k/3 = -9/3

k = -3

and thats the answer.

Hope this helps and have a great day!

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h(x)= \dfrac{1}{8} x^3 - x^2h(x)= 8 1 x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided b

Nesterboy [21]

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given the function $h(x)=\dfrac{1}{8}x^3-x^2$

The average rate of change of the function h(x) over the interval $a\le x\le b$ can be calculated using formula

$\dfrac{h(b)-h(a)}{b-a}$

In your case,

$a=-2,\\ \\b=2,$

so the average rate of change is

$\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}$