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3 years ago

11

Determine the stiffness of the spring to hold the 85-kg crate in the position shown.

1 answer:

GalinKa [24]3 years ago

5 0

Correct position spring hold it

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A force of 6N is exerted on a cart that is carrying a rock and produces an acceleration of 2 m/s2. If the cart has a mass of 1 k

vaieri [72.5K]

If you use the equation F=ma and re-arrange it to get m = F/a, you'll get the total mass. Then you have to subtract the mass of the cart from the total mass to get the mass of the rock.

Thus, m = 6N over 2m/s^2. The total mass will then be 3kg. Subtracting 1kg from the total mass will then yield you 2kg, which is the mass of the rock. Hope this helps.

6 0

2 years ago

Draw the Free- Body diagram of the 37 kilogram glass falling to the floor in a vacuum.

Alexus [3.1K]

Answer:

362.6 N

Explanation:

$F_{g}=mg$

$F_{g}=37\cdot9.8$

$F_{g}=362.6\ N$

Therefore, the force that the glass hits the floor with is 362.6 N

5 0

2 years ago

A stone is thrown vertically into the air at an initial velocity of 96 ft/s. On Mars, the height s (in feet) of the stone above

vladimir1956 [14]

Answer:

240 ft

Explanation:

t = Time taken

u = Initial velocity = 96 ft/s

v = Final velocity

s = Displacement

a = Acceleration = 12 m/s² on Mars 32 ft/s² on Earth negative due to upward direction

Mars

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=96\times t+\frac{1}{2}\times -12\times t^2\\\Rightarrow s=96t-6t^2\ ft$

Earth

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=96\times t+\frac{1}{2}\times -32\times t^2\\\Rightarrow s=96t-16t^2\ ft$

Differentiating the first equation with respect to time we get

$\frac{ds}{dt}=96-12t$

Equating with zero

$0=96-12t\\\Rightarrow t=\frac{96}{12}=8\ s$

Differentiating the second equation with respect to time we get

$\frac{ds}{dt}=96-32t$

Equating with zero

$0=96-32t\\\Rightarrow t=\frac{96}{32}=3\ s$

Applying the time taken to the above equations, we get

$s=96t-6t^2\ ft\\\Rightarrow s=96\times 8-6\times 8^2\\\Rightarrow s=384$

$s=96t-16t^2\\\Rightarrow s=96\times 3-16\times 3^2\\\Rightarrow s=144$

Difference in height = 384-144 = 240 ft

The stone will travel 240 ft higher on Mars

6 0

2 years ago

Suppose that two point charges, each with a charge of +1.00 C, are separated by a distance of 1.0 m. If the distance between the

Aleksandr-060686 [28]

Given:

The magnitude of each charge is q1 = q2 = 1 C

The distance between them is r = 1 m

To find the force when distance is doubled.

Explanation:

The new distance is

$\begin{gathered} r^{\prime}=\text{ 2r} \\ =2\times1 \\ =2\text{ }m \end{gathered}$

The force can be calculated by the formula

$F=k\frac{q1q2}{(r^{\prime})^2}$

Here, k is the constant whose value is

$k=9\times10^9\text{ N m}^2\text{ /C}^2$

On substituting the values, the force will be

$\begin{gathered} F=9\times10^9\times\frac{1\times1}{(2)^2} \\ =2.25\times10^9\text{ N} \end{gathered}$

7 0

9 months ago

PLEASE HELP ME PLEASE

Afina-wow [57]

Answer:

For A

Displacement= 1/2*3*6= 9m

For B

Displacement= 1/2*4*4= 8m

5 0

2 years ago