Question

What is the ph of a 0.027 M KOH solution?

Answer 1

First you calculate the concentration of [OH⁻] in solution :

POH  = - log [ OH⁻]

POH = - log [ 0.027 ]

POH = 1.56

PH + POH = 14

PH + 1.56 = 14

PH = 14 - 1.56

PH = 12.44

hope this helps!