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2 years ago

1-(1+.06/12) -12(30)

Mathematics

1 answer:

jekas [21]2 years ago

6 0

Answer:

−360.005

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I need help pleaseeee!!!!! I don’t understand

olganol [36]

Answer:

a. x = 5, m∠FGH = 22°

b. m∠HGI = 22°

c. m∠FGI = 44°

Step-by-step explanation:

Since GH bisects FGI this means it divides the angle in two equal parts.

a. solving for x means equating them:

5x-3 = 6x-8 =>

5x - 6x = 3 - 8 =>

x = 5.

Both m∠FGH and m∠HGI are 5*5-3 = 22°

c. Add both angles: m∠FGH + m∠HGI = 44°

8 0

2 years ago

Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217

Soloha48 [4]

Answer:

$f(216) \approx 6.0093$

Step-by-step explanation:

Given

$\sqrt[3]{217}$

Required

Solve

Linear approximated as:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

Take:

$x = 216; \triangle x= 1$

So:

$f(x) = \sqrt[3]{x}$

Substitute 216 for x

$f(x) = \sqrt[3]{216}$

$f(x) = 6$

So, we have:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

$f(215 + 1) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot f'(x)$

To calculate f'(x);

We have:

$f(x) = \sqrt[3]{x}$

Rewrite as:

$f(x) = x^\frac{1}{3}$

Differentiate

$f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}$

Split

$f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}$

$f'(x) = \frac{x^\frac{1}{3}}{3x}$

Substitute 216 for x

$f'(216) = \frac{216^\frac{1}{3}}{3*216}$

$f'(216) = \frac{6}{648}$

$f'(216) = \frac{3}{324}$

So:

$f(216) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot \frac{3}{324}$

$f(216) \approx 6 + \frac{3}{324}$

$f(216) \approx 6 + 0.0093$

$f(216) \approx 6.0093$

6 0

2 years ago

If f(x) = 4x + 12 is graphed on a coordinate plane, what is the y-intercept of the graph?

Tatiana [17]

Answer: y=12

Step-by-step explanation:

the y-intercept of the graph when : x=0

f(0) =4(0)+12 = 12

8 0

2 years ago

Read 2 more answers

What is 2 15/16 Ian’s a decimal?

Arada [10]

Answer:

2.9375

Step-by-step explanation:

15 divided by 16 equals .9375 so 2 15/16 is 2.9375

5 0

2 years ago

Point R is the midpoint of line QS. R is located at (5, -7.5) S is located at (-1,-13) What is the location of Point Q?

Lisa [10]

Answer: ( 11, -2 )

Step-by-step explanation:

The mid point of a line is calculated using the formula:

M = ( $\frac{x_{1}+x_{2}}{2}$ , $\frac{y_{1}+y_{2}}{2}$ )

From the question , the mid point is already given , substituting , we have :

(5 , - 7.5 ) = ( $\frac{x-1}{2}$ , $\frac{y-13}{2}$ )

Equating the x component to x and the y component to y , we have

5 = $\frac{x-1}{2}$

x - 1 = 10

x = 11

Also

- 7.5 = $\frac{y-13}{2}$

-15 = y - 13

-15 + 13 = y

Therefore : y = -2

Therefore : the location of point P is ( 11, -2 )

7 0

2 years ago