Question 5 is B
Question 9 is C
Using the normal distribution relation, the probability that sample will exceed the weight limit is 0.004
<u>Using the relation</u> ::
The mean, μ = np = (162 × 19) = 3078
The standard deviation, σ = 28 × √19 = 122.049
<u>The Zscore</u> :
Zscore = (3401 - 3078) ÷ (122.049)
Zscore = 2.65
Hence,
P(Z > 2.65) = 1 - P(Z < 2.65)
Using a normal distribution table :
P(Z > 2.65) = 1 - 0.9959
P(Z > 2.65) = 0.004
Learn more : brainly.com/question/25204474
Answer:
2/6
Step-by-step explanation:
Ok, so if the fraction is 1/3 and the denominator needs to be 6, then what you do is figure out what would turn 3 into 6. So, 3 x 2 would equal 6 and then you would have to also keep that two and multiply that 2 with the 1 and you would get 2. That would lead to the numerator being 2 and the denominator being 6, or 2/6.