N-Octanol and water are chosen because the connection between a substance's hydrophilicity and lipophilicity is measured by (n-Octanol/Water partition coefficient). When a chemical is more dissolves in fat-like solvents like n-octanol, the value is more significant than one, when it's more dissolved in water, the value is lower.
What is the partition coefficient?
- The partition coefficient for the two-phase network comprising n-octanol and water is known as the value. N-Octanol-Water Partition Ratio is another name for it.
- The connection between a substance's hydrophilicity (its ability to dissolve in water) and lipophilicity (its ability to dissolve in fat) is measured by . The value is bigger if a drug is more accessible in fat-like liquids like n-octanol and less if a compound seems more water-soluble.
- Owing to linkage or fragmentation, substances that are involved in the octanol-water combination as multiple synthetic entities are each given a unique ratio.
So, N-Octanol is chosen because it has a carbon/oxygen ratio that is comparable to that of lipids and because it shows both hydrophobic and hydrophilic properties. N-octanol, therefore, resembles the makeup and characteristics of cells and other living things.
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The volume of chlorine molecules produced at STP would be 96 dm³.
<h3>Stoichiometric problem</h3>
Sodium chloride ionizes during electrolysis to produce sodium and chlorine ions as follows:
This means that 1 mole of sodium chloride will produce 1 mole of sodium ion and 1 mole of chlorine ion respectively.
Recall that: mole = mass/molar mass
Hence, 234 g of sodium chloride will give:
234/58.44 = 4.00 moles.
Thus, the equivalent number of moles of chlorine produced by 234 g of sodium chloride will be 4 moles.
Recall that:
1 mole of every gas at Standard Temperature and Pressure = 24 Liters.
Hence:
4 moles of chlorine = 4 x 24 = 96 Liters or 96 dm³.
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Answer:-
Explanations:- The first reaction is combustion reaction as the hydrocarbon is burned in presence of oxygen to give carbon dioxide and water.
Second reaction is the synthesis reaction as in general a synthesis reaction looks like:
Third reaction is the decomposition reaction as it looks opposite of synthesis reaction.
In general, a single displacement reaction looks like:
Fourth reaction is single replacement reaction as bromine is replaced by chlorine.
So, the correct choice is the last reaction, .
NH₃:
N = 8*10²²
NA = 6.02*10²³
n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol
O₂:
N=7*10²²
NA = 6.02*10²³
n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol
4NH₃ <span>+ 3O</span>₂ ⇒<span> 2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol : 3mol : 2mol
0.133mol : 0.116mol : 0,0665mol
limiting reactant
N₂:
n = 0.0665mol
M = 28g/mol
m = n*M = 0.0665mol*28g/mol = <u>1,862g</u>