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2 years ago

Solve for x.-4 - 2x = 43x = [?]

Mathematics

1 answer:

aniked [119]2 years ago

3 0

The answer is -4
I have to type this cuz it won’t let me send

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Given right triangle ABCABC with altitude \overline{BD}

Alex

Answer:

$x = 2\sqrt{11}$

Step-by-step explanation:

AD = 4

AC = 11

DC = 11 - 4 = 7

First, find BD using the right triangle altitude theorem:

$BD = \sqrt{AD*DC}$

Plug in the values

$BD = \sqrt{4*7}$

$BD = 2\sqrt{7}$

Use pythagorean theorem to find x:

x² = AD² + BD²

Plug in the values

$x^2 = 4^2 + (2\sqrt{7})^2$

$x^2 = 16 + (4*7)$

$x^2 = 16 + 28$

$x^2 = 44$

Take the square root of both sides

$\sqrt{x^2} = \sqrt{44}$

$x = \sqrt{44}$

$x = \sqrt{4 * 11}$

$x = 2\sqrt{11}$

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Step-by-step explanation:

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2 years ago

Solve for x.-4 - 2x = 43x = [?]​

Solve for x.-4 - 2x = 43x = [?]