The work done is 400 J
Explanation:
The work done by you in pushing the box along the slope is given by
where
F is the magnitude of the force applied
d is the distance covered by the box along the slope
Here we have the following:
F = 200 N is the magnitude of the force applied
is the distance covered, where
h = 1 m is the vertical rise
is the slope of the plane
Substituting and solving, we find
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Answer:
46.2 rad/s2
Explanation:
Angular acceleration works very similar to linear acceleration, it follows this equation:
Where:
γ: angular acceleration
Mt: torque
J: moment of inertia of the load from its turning axis
Since we have the torque we just need the moment of inertia. We have to add together the moments of the drive shaft, tires, wheel walls and wheels.
The wheels act like disks. For disks the moment of inertia is:
The wheel walls act like annular rings, for these the moment of inertia is:
The tread acts like a hoop, as in mass concentrated into a circunference, for these:
The axle acts like a rod, which is the same as the disk:
The drive shaft acts like a rod too:
SO, the total moment of inertia is:
J = 2*Jwheel + 2*Jwall + 2*Jtread + Jaxle + Jshaft
J = 2*0.243 + 2*0.07 + 2*1.09 + 0.0028 + 0.016 = 2.82 kg*m2
Finally the angular acceleration is: