The appropriate response is the Aneroid barometer. This kind of gauge has an incompletely cleared chamber that progressions shape, packing as barometrical weight increments and growing as weight declines.
I hope the answer will help you.
It would take 30 minutes
You would do 15.0 divided by 0.5
Answer:
Check the explanation
Explanation:
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
The image is virtual
The image is upright
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
Kindly check the diagram in the attached image below.
Answer:
<em>k = 25.18 N/m</em>
Explanation:
<u>Simple Harmonic Oscillator</u>
It consists of a weight attached to one end of a spring being allowed to move forth and back.
If m is the mass of the weight and k is the constant of the spring, the period of the oscillation is given by:
If the period is known, we can find the value of the constant by solving for k:
Substituting the given values m=5 Kg and T=2.8 seconds:
k = 25.18 N/m
Answer:
He is warmed up now
Explanation:
His muscles are better and stretched now