plzzzz answer right away will mark BRAINLIST AND FIVE STARS PLUS THANKS What is the constant of proportionality in the equation
2 answers:
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Answer:
see below
Step-by-step explanation:
The idea is you're trying to find quotient values that get you close to the dividend value when they're multiplied by the divisor.
In the left panel, you are basically looking at 8/3 ≈ 2. Since that is 8 tens, the partial quotient is 2 tens, or 20. The value of that multiplied by the divisor (3) is what gets subtracted from 87 for the next effort.
That difference (27) is the new dividend at the top of the right panel. The line below it (-27) is the result of multiplying the partial quotient by 3. Hence, that partial quotient on the top line must be 9. We want the difference at the bottom of the right panel to be zero.
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In case you didn't know already that 87/3 = 29, you could work backwards. Starting from 0 at the bottom right, you would fill in the boxes above that, then copy the top box in that panel (27) to the difference at the bottom of the left panel. Of course, the middle number there must be 60 for the difference to be 27. That is 3·20, meaning the partial quotient at left on the top line is 20.
