Time
Explanation:
it changes over time because it changes the organism over time
<h2>Sequence code </h2>
Explanation:
DNA template (non coding strand) is always synthesized from 3'-5' direction and the complementary strand (coding strand) will be synthesized from 5'-3' direction; mRNA synthesized will be from 5'-3' direction and will have the same sequence as coding strand(only in place of T, U will be present)
Sequence 1: 3' TACGCTACGATCGTA 5'
Coding strand 1 : 5' ATGCGATGCTAGCAT 3'
mRNA 1: 5' AUGCGAUGCUAGCAU 3'
AUG codes for methionine(Met); CGA codes for alanine(Ala); UGC codes for threonine(Thr); UAG codes for isoleucine(Iso); CAU codes for valine(Val)
so protein 1 will be:
Met-Ala-Thr-Iso-Val
Sequence 2: 3' TACGCTACTATCGTA 5'
Coding strand 2: 5' ATGCGATGATAGCAT 3'
mRNA 2; 5' AUGCGAUGAUAGCAU 3'
AUG codes for methionine(Met); CGA codes for alanine(Ala); UGA codes for threonine(Thr); UAG codes for isoleucine(Iso); CAU codes for valine(Val)
so protein 2 will be:
Met-Ala-Thr-Iso-Val
Both the protein sequence comes out to be same hence function of protein 2 will be same as that of protein 1
The answer is ribosomes. Ribosomes produce proteins for the cell.
I think this is what you’re looking for hopefully
Answer:
The tall parent was heterozygous
Explanation:
If tall height is dominant to short height the only genotype possible for short height is hh, while there are two possible genotypes for tall height, Hh and HH. When HH is crossed with hh all the offspring are Hh, but if Hh is crossed with hh, a quarter of the offspring is HH, a quarter is hh and half is Hh. If the tall pea plants were HH there would only be tall offspring, but because there are some short offspring we know that the tall pea plants must have a genotype of Hh.
