talk to them.try to get them to understand you.
Answer:
a) nearest jump is JL = 1380 inches = 115ft
b) number of jumps in 1 mile N= 46 jumps
Step-by-step explanation:
Given that the jump length is proportional to the body length.
If 2 inch grasshopper can jump 40 inches.
JL = k(BL)
k = JL/BL
where JL = jump length = 40 inches
BL = Body length = 2 inches.
k = 40/2 = 20
The constant of proportionality is 20.
For the athlete :
BL = 5ft 9 inches = 5(12)+9 = 69 inches.
The jump length of the athlete is:
JL = k(BL) = 20(69)
JL = 1380 inches. = 115ft
The number of jumps in 1 mile is
1 mile = 63360 inches
N = 63360/1380
N = 45.9 = 46
N= 46
Therefore, 46 jumps would be needed.
Answer:
Not sure but :
Y=15/7
X=13/5
Z=26/7
I will check them later and tell you if they are right or not .
Step-by-step explanation:
y power 2 : 31 × 8 = 248
Rad 248 = 15/7
x power 2 : 23 × 8 = 184
Rad 184 = 13/5
31 power 2 : (15/7) power 2 + z power 2
961 = 246/49 + z powe 2
z power 2 = 714/51
rad 714/51 = 26/7
z = 26/7
Answer:
The scale factors that make figure smaller are the option D. -0.5 and the option E. 0.25
Step-by-step explanation:
we know that
If the absolute value of the scale factor is greater than 1, then the image will be larger than the pre-image.
If the absolute value of the scale factor is less than 1, then the image will be smaller than the pre-image.
If the absolute value of the scale factor is equal to 1, then the image will be the same size than the pre-image.
Additionally, a negative scale factor causes the dilation to rotate 180 degrees
therefore
In this problem
The scale factors that make figure smaller are the option D. -0.5 and the option E 0.25
P = 2 x ( W+L)
P = 2 x (W + 2W)
p = 2 x 3W
P = 2 x 3(20/3) =40