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2 years ago

The single factor tested in an experiment is:

Mathematics

2 answers:

Slav-nsk [51]2 years ago

7 0

The single factor tested in an experiment is: THE VARIABLE.

Zepler [3.9K]2 years ago

3 0

Answer:

The answer is variable.

Step-by-step explanation:

The single factor tested in an experiment is - The variable

Variable is an element or factor that is meant to vary or change in an experiment. Variables are used in Algebra where they are used as a defining variable or 'x' to describe any number.

The variables can be - independent variables, dependent variables, constant variables etc.

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Write the equation of the line perpendicular to 4x – 5y = -10 through the point (2, 3). Write the equation in slope intercept fo

user100 [1]

I hope this helps you

7 0

2 years ago

Which of the following is a nonlinear function

pogonyaev

Answer:

Linear functions are equations where the greatest power of the variable (typically x) is 1;

They are graphed as straight lines;

So, any function that has the following format:

f(x) = ax + b;

Nonlinear functions would be any equation that has a variable to a power greater than 1;

This could be a quadratic equation or an exponential equation

6 0

1 year ago

How to do 264 in Expanded form

Setler [38]

Answer:

200+60+4

Step-by-step explanation:

200+60+4=264

6 0

2 years ago

Hi! I need help with the attached question in calc. Thank you:)

Elena L [17]

Answer:

3π square units.

Step-by-step explanation:

We can use the disk method.

Since we are revolving around AB, we have a vertical axis of revolution.

So, our representative rectangle will be horizontal.

R₁ is bounded by y = 9x.

So, x = y/9.

Our radius since our axis is AB will be 1 - x or 1 - y/9.

And we are integrating from y = 0 to y = 9.

By the disk method (for a vertical axis of revolution):

$\displaystyle V=\pi \int_a^b [R(y)]^2\, dy$

So:

$\displaystyle V=\pi\int_0^9\Big(1-\frac{y}{9}\Big)^2\, dy$

Simplify:

$\displaystyle V=\pi\int_0^9(1-\frac{2y}{9}+\frac{y^2}{81})\, dy$

Integrate:

$\displaystyle V=\pi\Big[y-\frac{1}{9}y^2+\frac{1}{243}y^3\Big|_0^9\Big]$

Evaluate (I ignored the 0):

$\displaystyle V=\pi[9-\frac{1}{9}(9)^2+\frac{1}{243}(9^3)]=3\pi$

The volume of the solid is 3π square units.

Note:

You can do this without calculus. Notice that R₁ revolved around AB is simply a right cone with radius 1 and height 9. Then by the volume for a cone formula:

$\displaystyle V=\frac{1}{3}\pi(1)^2(9)=3\pi$

We acquire the exact same answer.

8 0

2 years ago

What is the value of the expression x^2y–y+xy^2–x for x=4 and y=0.25?

stepan [7]

Answer:

0 (zero)

Step-by-step explanation:

${x}^{2} y - y + x {y}^{2} - x \\ = {4}^{2} \times 0.25 - 0.25 + 4 \times {0.25}^{2} - 4 \\ = 16 \times 0.25 - 0.25 + 4 \times 0.0625- 4 \\ = 4 - 0.25 + 0.25 - 4 \\ = 0 \\ \\ \purple {\boxed{ \bold{ \therefore \: {x}^{2} y - y + x {y}^{2} - x = 0}}}$

8 0

2 years ago