Line1: y = -x + 2
Line2: y = 2x - 1
Solution: (1,1)
Answer:
Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) =
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) =
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
Answer:
imm a bit sorry I could only answer the international one as the national is equal to international place value system
Step-by-step explanation:
eight hundred ninety three thousand four hundred fifty one
hth tth th h t o
8 9 3 4 5 1
I hope you understand
Answer:
the answer is 10x^2-30x+20
Step-by-step explanation:
you have to distribute the numbers and multiply then add the matching variables.
Answer:
sdasf sdf
Step-by-step explanation:
so how you ahsbdgkjsgdejgwqjda is how you ajsdbguyaweguidasdh to the question