F(x)=x^3-7x-6 Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P
x-(f(x)/(dy/dx))
x-(x^3-7x-6)/(3x^2-7)
(2x^3+6)/(3x^2-7), letting x1=0
0, -6/7, -.988, -.9999, -.99999999999, -1
(x^3-7x-6)/(x+1)
x^2 r -x^2-7x-6
-x r -6x-6
-6 r 0
(x+1)(x^2-x-6)=0
(x+1)(x-3)(x+2)=0
x= -2, -1, 3
Answer:
D) u=4 , v=2
Step-by-step explanation:
This is as 60 30 90 triangle.
One leg is x
Second is x sqrt 3
The hypotenuse is x(2)
So hope that helps
The correct answer for the question that is being presented above is this one: "Nine seconds." A firecracker shoots up from a hill 150 feet high, with an initial speed of 110 feet per second. Using the formula H(t) = −16t2 + vt + s, approximately the firecracker will hit the ground in <span>Nine seconds </span>
Answer:
... a line with an S curve ...
Step-by-step explanation:
Only the last choice passes the vertical line test for a function: no vertical line can intersect the graph at more than one point.