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2 years ago

I need help with question number 8. Someone please help me!

Mathematics

2 answers:

gtnhenbr [62]2 years ago

6 0

Answer:

L. 35-x

Step-by-step explanation:

The questions says "this was x dollars more than you earned thursday" So in this situation we are trying to find how much exactly more did you earn or how much was thursday's earning.

Therefore 35-x works because since you made 35 Saturday which is the higher amount than what you made on Thursday as indicated by question.

what you made of saturday-how much more it was compared to thursday= gives you what you made thursday!

Aloiza [94]2 years ago

4 0

Answer:

the answer is g and here's what it says you earned $35 mowing lawns this was a tax dollars more than you earn on Thursday so that would be x + 35

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Lerok [7]

The angle immediately below x makes up the third angle of the isosceles triangle whose base angles are 55°. That third angle and x are "vertical" angles, hence equal. The value of x can be found from the sum of angles of a triangle:
x + 55° + 55° = 180°
x = 70°

The appropriate choice is the 2nd one:
70°

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2 years ago

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Is step 3 correct or would I change 5/2 into a decimal?

Rzqust [24]

Answer:

keep it man u will do ok just be careful with other problems

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Sam has 15 identical rectangular windows in his home. The length of each window is twice the width, and the area of each window

marshall27 [118]

The answe would be 300 because, the perimeter of the windows is 12, then you have to multiply 25 to 12 then bam you get 300, yay!

5 0

2 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

$\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}$

7 0

1 year ago

Can anyone help me with this

Wittaler [7]

I believe the right anwser is c

4 0

2 years ago