Answer:
Choice C; The flight will be late on one of the three days.
Step-by-step explanation:
The flight is 75% of the time. This means that out of 4 flights, 3 are on time and the result of Franc's spinner should reflect this fact, i.e his spinner should give 75% probability of flights on time.
Choice A says the flight is on time 0% of the time, This is not true, therefore this is not a correct interpretation of the three spins.
Choice B says the flight is on time 100% of the time, This is not true, therefore this is not a correct interpretation of the three spins.
Choice C says the flight is on time 66% of the time, which is close to 75%. Therefore this choice is close and correct.
Choice D says the flight is on time 30% of the time, This is not true, therefore this is not a correct interpretation of the three spins.
Thus only choice C is correct.
Answer:
14.1
Step-by-step explanation:
0^9 +7x+189yx−3y
o
9
+7x−3y
9
+7x+3y
9
−7x−3y
9
−7x+3y
9
+7x+189yx−3y
2 Collect like terms.
{o}^{9}+(7x+7x-7x-7x+7x)+(-3{y}^{9}+3{y}^{9}-3{y}^{9}+3{y}^{9})+189yx-3y
o
9
+(7x+7x−7x−7x+7x)+(−3y
9
+3y
9
−3y
9
+3y
9
)+189yx−3y
3 Simplify.
{o}^{9}+7x+189yx-3y
o
9
+7x+189yx−3y
Answer:
see explanation
Step-by-step explanation:
Given the 2 equations
5x + y = 21 → (1)
x - 3y = 9 → (2)
Multiply (1) by 3 and add the result to (2) to eliminate y term
15x + 3y = 63 → (3)
Add (2) and (3) term by term
(x + 15x) + )- 3y + 3y) = (9 + 63)
16x = 72 ( divide both sides by 16 )
x = 4.5
Substitute x = 4.5 into (1) for corresponding value of y
22.5 + y = 21 ( subtract 22.5 from both sides )
y = - 1.5
Solution is (4.5, - 1.5 )
