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2 years ago

Given f(x) = - 3x - 2 and g(x) = - 2x - 4 , find h(x) = g(x) - f(x) .

Mathematics

1 answer:

Hunter-Best [27]2 years ago

8 0

Answer:

Therefore,

$h(x)=x-2$

Step-by-step explanation:

Given:

f(x) = - 3x - 2 and

g(x) = - 2x - 4 ,

To Find:

h(x) = g(x) - f(x)= ?

Solution:

We require,

$h(x) = g(x) - f(x)$

Substituting f(x) and g(x) we get

$h(x) = (-2x-4)-(-3x-2)\\\\h(x) =(-2x-4) +3x+2......Minus\ sign\ will\ go\ into\ bracket\\\\\therefore h(x)=x-2$

Therefore,

$h(x)=x-2$

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How to do this plastic help

liraira [26]

Answer:

39 degrees

Step-by-step explanation:

by seeing the diagram in the attachment, we can see that the angles UWV and VWX are on straight line or, their sum makes 180 degrees.

we also know that sum of the angles in a triangle is 180 degrees.

by using the first statement,

UWV + VWX = 180

UWV + 6x-3 = 180

UWV = 180+3-6x

= 183-6x

by using second statement,

UWV+WVU+VUW=180

substituting the values,

183-6x+2x+5+x+13=180

201-3x=180

substracting 180 from both sides,

21=3x

dividing both the sides by 3,

7=x

the angle VWX=6x-3

substituting 7=x,

VWX=6(7)-3= 39.

4 0

2 years ago

Name a pair of Alternate Exterior Angles

pogonyaev

Answer:

M, Z

O, X

P, W

N, Y

Step-by-step explanation:

They are all Alternate Exterior Angles.

<em>Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a great day!</em>

4 0

1 year ago

Read 2 more answers

Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7

Dima020 [189]

Answer:

The rational zero of the polynomial are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$ .

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

$\dfrac{\textrm factor of P}{\textrm factor Q}$ ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial , P = -7 , Q = 4

Now , $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$

I.e $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$ = $\frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }$

Or, The rational zero are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$

Hence The rational zero of the polynomial are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$ . Answer

7 0

2 years ago

Is my Answers Correct? Very easy Question!

Aliun [14]

Answer:

Step-by-step explanation:

Correct

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2 years ago

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The points (12, 23) and (14, 45) lie on a line. What is<br> the slope of the line?

ozzi

Answer:

slope= 11

Step-by-step explanation:

(12,23) = (x1,y1)

(14,45) = (x2,y2)

Now,

slope(m)= (y2-y1)/(x2-x1)

=(45-23)/(14-12)

=22/2

=11

5 0

2 years ago