A thin sheet of aluminum can block _____.
1 answer:
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Answer:
2,57 g of precipitate.
Explanation:
For the reaction:
6 NaOH + Al₂(SO₄)₃ → 2 Al(OH)₃ + 3 Na₂SO₄
The precipitate is Al(OH)₃.
185,5mL of 0,533M NaOH are:
0,1855L × 0,533M = <em>0,0989 moles NaOH</em>
Moles of Al₂(SO₄)₃ are:
15,8g × = <em>0,0462 moles Al₂(SO₄)₃</em>
For the total reaction of 0,0989 moles NaOH with Al₂(SO₄)₃ you need:
0,0989moles NaOH × = <em>0,0165 moles Al₂(SO₄)₃</em>
As you have <em>0,0462 moles Al₂(SO₄)₃ </em>the limiting reactant is NaOH.
0,0989 moles of NaOH produce:
0,0989moles NaOH × = <em>0,0330 moles of Al(OH)₃</em>
These moles are:
0,0330 moles of Al(OH)₃ × (78 g/mol) = <em>2,57 g of Al(OH)₃ ≡ mass of precipitate</em>
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Answer:
Decreases
Explanation:
The atmospheric pressure on the surface of the mercury pushes it up the evacuated tube until the downward pressure of the mercury equals the atmospheric pressure.
If the atmospheric pressure decreases, the mercury doesn't have to rise as high.
The mercury height decreases.
