Answer:- ![[Na_2CO_3]=0.254M](https://tex.z-dn.net/?f=%5BNa_2CO_3%5D%3D0.254M)
, ![[Na^+]=0.508 M](https://tex.z-dn.net/?f=%5BNa%5E%2B%5D%3D0.508%20M)
, ![[CO_3^2^-]=0.254M](https://tex.z-dn.net/?f=%5BCO_3%5E2%5E-%5D%3D0.254M)
Solution:- We are asked to calculate the molarity of sodium carbonate solution as well as the sodium and carbonate ions.
Molarity is moles of solute per liter of solution. We have been given with 6.73 grams of sodium carbonate and the volume of solution is 250.mL. Grams are converted to moles and mL are converted to L and finally the moles are divided by liters to get the molarity of sodium carbonate.
Molar mass of sodium carbonate is 105.99 gram per mol. The calculations for the molarity of sodium carbonate are shown below:
= 
So, molarity of sodium carbonate solution is 0.254 M.
sodium carbonate dissociate to give the ions as:
There is 1:2 mol ratio between sodium carbonate and sodium ion. So, the molarity of sodium ion will be two times of sodium carbonate molarity.
![[Na^+]=2(0.254M)](https://tex.z-dn.net/?f=%5BNa%5E%2B%5D%3D2%280.254M%29)
= 0.508 M
There is 1:1 mol ratio between sodium carbonate and carbonate ion. So, the molarity of carbonate ion will be equal to the molarity of sodium carbonate.
Answer:
If the moles of gas are tripled, the volume must also triple.
Explanation:
According to Avogadro law,
Equal volume of all the gases at same temperature and pressure have equal number of molecules.
The number of moles and volume are directly related to each other. By increasing the number of moles volume also goes to increase with same ratio.
When number of moles decreases the volume also goes to decrease at constant temperature and pressure.
Mathematical expression:
V ∝ n
V = Kn
V/n = k
When volume is changed from V₁ to V₂ by changing the number of moles from n₁ to n₂. Then expression will be,
V₁/n₁ = V₂/n₂
Answer:
0.85 Molar Na2O
Explanation:
Determine the moles of sodium oxide, Na2O, in 10 grams by dividing by the molar mass of Na2O (61.98 g/mole).
(10 g Na2O)/(61.98 g/mole) = 0.161 moles Na2O.
Molar is a measure of concentration. It is defined as moles/liter. A 1 M solution contains 1 mole of solute per liter of solvent. [200 ml water = 0.2 Liters water.]
In this case, we have 0.161 moles Na2O in 0.200 L of solvent.
(0.161 moles Na2O)/(0.200 L) = 0.85 Molar Na2O
Answer:
I think its the last one
Explanation:
its supposed to be H 2 O 2.
