Well, at the END of 100, none excluding post decimal zeroes, including them there are infinite. If you meant how many zeroes inside 100, 2 then.
Answer:
f(9)=54
Step-by-step explanation:
Subsitute 9 for x in f(x)=6x
Answer:
I think z = 89 and I don’t know x
Answer:
part A: expression 1: 6(8m+2)
expression 2: 6m+12+42m
Part B: 6(m+2+7m)= 6(8m+2)
combine like terms is 6(m+2+7m), so it is 6(2+8m) or 6(8m+2)
6(8m+2)= 6(8m+2)
Part C: 6m+12+42m=6(m+2+7m)
m=0
6(0+2+7(0))=6(0)+12+42(0)
6(2)= 12
12=12
It is true hope this helped
