All categories

2 years ago

Please help me with this problem (:

Mathematics

2 answers:

Ket [755]2 years ago

8 0

Answer:

f(x)=-2*(x-3)+5 when x<3

g(x)=x(x-3)+5 when x>3

Step-by-step explanation:

| | is absolute function meaning the value must be larger than or equal to zero.

So | x-3 | = -(x-3) when x<3

f(x)=-2*(x-3)+5 when x<3

| x-3 | = (x-3) when x>3

g(x)=2*(x-3)+5 when x>3

valentina_108 [34]2 years ago

7 0

Answer:

$f(x) = -2( x - 3) + 5, x \leq 3\\\\g(x) = 2(x-3)+5, x > 3$

Step-by-step explanation:

turning pt of the abs fn |x-3| is at x=3

$2|x-3|=-2(x-3), x\leq 3\\\\2|x-3|=2(x-3), x>3$

$f(x) = -2( x - 3) + 5, x \leq 3\\\\g(x) = 2(x-3)+5, x > 3$

You might be interested in

700 divided by 12 Please help me

kogti [31]

700/12 equals 58 and 1/3.

6 0

2 years ago

Read 2 more answers

HELP ASAP The graph shows the relationship between time, in hours, and the population, in thousands of a culture of bacteria. y

Harrizon [31]

Answer:

I’m doing that exact question right now on a test so I just guessed

Step-by-step explanation:

3 0

2 years ago

The claim is that the proportion of adults who smoked a cigarette in the past week is less than 0.30, and the sample statistics

IrinaK [193]

Answer: 0.84

Step-by-step explanation:

let p be the population proportion of adults who smoked a cigarette in the past week.

As per given , we have

$H_a: p$

Sample size : n= 1491

The sample proportion of adults smoked a cigarette= $\hat{p}=\dfrac{x}{n}=\dfrac{462}{1491}=0.30985915493\approx0.31$

The test statistic for proportion is given by :-

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Substitute all the values , we get

$z=\dfrac{0.31-0.30}{\sqrt{\dfrac{0.30(1-0.30)}{1491}}}\\\\=\dfrac{0.01}{\sqrt{0.000141}}\\\\=\dfrac{0.01}{0.011874342087}=0.84261497731\approx0.84$

Hence, the value of the test statistic = 0.84

6 0

2 years ago

I need you help I don’t have answer

Anvisha [2.4K]

x/3 = 9/5

x = (9*3)/5

x= 5.4

8 0

2 years ago

12What mistake did the student make when solvingtheir two-step equation?(a)b) If correctly solved what should the value of be?

mixas84 [53]

Given the equation:

$\frac{x}{6}+3=-18$

(a) You can identify that the student applied the Subtraction Property of Equality by subtraction 3 from both sides of the equation:

$\frac{x}{6}+3-(3)=-18-(3)$

However, the student made a mistake when adding the numbers on the right side.

Since you have two numbers with the same sign on the right side of the equation, you must add them, not subtract them and use the same sign in the result. Then, the steps to add them are:

- Add their Absolute values (their values without the negative sign).

- Write the sum with the negative sign.

Then:

$\frac{x}{6}=-21$

(b) The correct procedure is:

1. Apply the Subtraction Property of Equality by subtracting 3 from both sides (as you did in the previous part):

$\begin{gathered} \frac{x}{6}+3-(3)=-18-(3) \\ \\ \frac{x}{6}=-21 \end{gathered}$

2. Apply the Multiplication Property of Equality by multiplying both sides of the equation by 6:

$\begin{gathered} (6)(\frac{x}{6})=(-21)(6) \\ \\ x=-126 \end{gathered}$

Hence, the answers are:

(a) The student made a mistake by adding the numbers -18 and -3:

$-18-3=-15\text{ (False)}$

(b) The value of "x" should be:

$x=-126$

4 0

8 months ago