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2 years ago

A sample of hydrogen gas has an initial pressure of 2.86 atm and an initial volume of 8472 mL If the volume of the

Chemistry

1 answer:

Oliga [24]2 years ago

5 0

<h3>Answer:</h3>

Gas law : Boyle's law

New pressure: 66.24 atm

<h3>Explanation:</h3>

Concept tested: Gas laws (Boyle's law)

<u>We are given,</u>

Initial pressure, P₁ = 2.86 atm
Initial volume, V₁ = 8472 mL
New volume, V₂ IS 365.8 mL

We need to determine the new pressure, P₂

According to Boyle's law , the volume of a fixed mass of a gas and the pressure are inversely proportional at constant temperature.

That is, $P\alpha \frac{1}{V}$
This means , PV = k (constant)
Therefore; P₁V₁ = P₂V₂

Rearranging the formula, we can get the new pressure, P₂

P₂ = P₁V₁ ÷ V₂

= (2.86 atm × 8472 mL) ÷ 365.8 mL

= 66.24 atm

Therefore, the new pressure is 66.24 atm

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Explanation:

The concept of arrehenius equation is used to calculate the activation energy.

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1 year ago

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A beaker holds 962 g of a brine solution that is 6.20 percent salt. If 123g of water are evaporated from the beaker, how much sa

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Answer:

13.687 grams of salt should be added

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Explanation:

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Salt= 6.2%

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962 gram of water is made up of:

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If we add x gram of salt for making brine solution up to 8.6%

=(59. 644g + x)g.of salt

% salt = Mass of Salt / Total mass of solution

= 0.086= 59.644 + x / 779.356 + 59.644 + x

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x= 13.687 g of salt

Grams of 8.6% brine solution will be:

Gram of water + total gram of salt added to form 8.6% brine solution.

= 779.356g +59.644g + 13.687g

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2 years ago

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How many joules of heat are required to heat 25.0 g of isopropyl alcohol from the prevailing room temperature, 21.2 oC, to its b

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Answer:

3984.12 J joules of heat are required to heat 25.0 g of isopropyl alcohol to its boiling point.

Explanation:

$Q=m\times c\Delta T=m\times c\times (T_2-T_1)$

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Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance

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$T_2$ = Final temperature of the substance

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Heat absorbed by the isopropyl alcohol to boil:

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