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2 years ago

PLEASE HELP!!! FIRST IS BRAINLIEST!!!

2 answers:

7 0

The material or substance that a wave moves through is called a medium. The medium affects the speed of the wave that passes through it. One factor that affects the speed of a wave is the type of medium. Some waves move faster in solids and some waves move faster in liquids and gases. Another factor that affects wave speed is the temperature of the medium.

Verizon [17]2 years ago

6 0

1. A Medium

2. One of these 4, the refractive index of the medium <span>Choose whichever are on the test.

3. </span>properties and nature of medium, Hope this helps.

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A small rubber ball is thrown at a heavier, larger basketball that is still. The small ball bounces off the basketball. Assume t

meriva

Part A.
The forces are the same because the force from the smaller ball it transferring its Energy through the basketball and it's rebounding as Connecticut Energy back up to the smaller ball

6 0

2 years ago

Read 2 more answers

Which will a positively charged objects attract

Vitek1552 [10]

Me and you! enjoy your day girllllaa or boy

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2 years ago

Read 2 more answers

Susan's 10.0kg baby brother Paul sits on a mat. Susan pulls the mat across the floor using a rope that is angled 30? above the f

elena-s [515]

Answer:

The speed after being pulled is 2.4123m/s

Explanation:

The work realize by the tension and the friction is equal to the change in the kinetic energy, so:

$W_T+W_F=K_f-K_i$ (1)

Where:

$W_T=T*x*cos(0)=32N*3.2m*cos(30)=88.6810J\\W_F=F_r*x*cos(180)=-0.190*mg*x =-0.190*10kg*9.8m/s^{2}*3.2m=59.584J\\ K_i=0\\K_f=\frac{1}{2}*m*v_f^{2}=5v_f^{2}$

Because the work made by any force is equal to the multiplication of the force, the displacement and the cosine of the angle between them.

Additionally, the kinetic energy is equal to $\frac{1}{2}mv^{2}$ , so if the initial velocity $v_i$ is equal to zero, the initial kinetic energy $K_i$ is equal to zero.

Then, replacing the values on the equation and solving for $v_f$ , we get:

$W_T+W_F=K_f-K_i\\88.6810-59.5840=5v_f^{2}\\29.097=5v_f^{2}$

$\frac{29.097}{5}=v_f^{2}\\\sqrt{5.8194}=v_f\\2.4123=v_f$

So, the speed after being pulled 3.2m is 2.4123 m/s

8 0

2 years ago

Raindrops fall vertically at 7.5 m/s relative to the Earth. What does an observer in a car moving at 20.2 m/s in a straight line

Vilka [71]

Answer:

vDP = 21.7454 m/s

θ = 200.3693°

Explanation:

Given

vDE = 7.5 m/s

vPE = 20.2 m/s

Required: vDP

Assume that

vDE to be in direction of - j

vPE to be in direction of i

According to relative motion concept the velocity vDP is given by

vDP = vDE - vPE (I)

Substitute in (I) to get that

vDP = - 7.5 j - 20.2 i

The magnitude of vDP is given by

vDP = √((- 7.5)²+(- 20.2)²) m/s = 21.7454 m/s

θ = Arctan (- 7.5/- 20.2) = 20.3693°

θ is in 3rd quadrant so add 180°

θ = 20.3693° + 180° = 200.3693°

4 0

2 years ago

Use the motion map to answer the question.

Lana71 [14]

Answer:

The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.

3 0

2 years ago