Answer:
x =0, x =4, x = 4
Step-by-step explanation:
Given: f(x) =
To find the zeros, we need to plug in f(x) = 0, we get
Here x is the common factor, so we can take it out.
Now we can factorize
So
x(x^2 - 8x -16) = 0
x(x-4)(x-4) = 0
x = 0, (x -4) = 0, x-4 = 0
x =0, x = 4, x = 4
Here the two roots are real and equal.
Therefore, the zeros of the given function are x =0 and x = 4 and x = 4