The height of the isosceles triangle is 8.49 inches.
<h3>
How to find the height of the triangle?</h3>
Here we have a triangle such that two of the sides measure 9 inches, and the base measures 6 inches.
So this is an isosceles triangle.
We can divide the isosceles triangle into two smaller right triangles, such that the side that measures 9 inches is the hypotenuse, the base is 3 inches, and the height of the isosceles triangle is the other cathetus.
By Pythagorean's theorem, we can write:
(9in)^2 = (3 in)^2 + h^2
Where h is the height that we are trying to find.
Solving that for h we get:
h = √( (9 in)^2 - (3in)^2) = 8.49 inches.
We conclude that the height of the isosceles triangle is 8.49 inches.
If you want to learn more about triangles:
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Answer:
1 1/4
Step-by-step explanation:
turn the 2 into decimals and then subtract and you get 1.25 and that aa a fraction is 1 1/4
<span>The number of x-intercepts that appear on the graph of the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)
Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0
Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2
(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2
(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
Answer: X = 7√2
Step-by-step explanation:
Let first Consider triangle BDC,
Cos C = adjacent/ hypothenus
Cos C = 7 / x ...... (1)
Also, let consider triangle ABC
Cos C = adjacent / hypothenus
Cos C = x / 14 ....... (2)
Since angle C is the same, equate equation 1 to 2
7/ x = x / 14
Cross multiply
X^2 = 98
Make x the subject of formula
X = sqrt (98)
X = sqrt ( 49 × 2 )
X = sqrt (49) × sqrt (2)
X = 7 sqrt(2)
X = 7√2