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2 years ago

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How much change will you get back if you bought 3 $0.99 chocolate bars and paid with $5 bill

1 answer:

Molodets [167]2 years ago

4 0

You will get $2.03 back in change

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Use the laws of logarithms and the values given below to evaluate the logarithmic expression (picture provided)

nydimaria [60]

Answer: Option a.

Step-by-step explanation:

To solve the given exercise, you must keep on mind the law of logarithms shown below:

$log(a)-log(b)=log(\frac{a}{b})$

Therefore, by applying the law , you can rewrite the expression given, as following:

$log(\frac{5}{7})=log(5)-log(7)$

You know that:

$log5=0.6990\\log7=0.8451$

Then, when you substitute values, you obtain:

$0.6990-0.8451=-0.1461$

4 0

2 years ago

Read 2 more answers

A honda civic gets 34 miles per gallon when driving in town. The same car gets 42 miles per gallon when driving on the highway.

pogonyaev

5 gallons = 170
10 gallons = 340
15 gallons = 510
20 gallons = 680
25 gallons = 850

8 0

2 years ago

Read 2 more answers

I need help on this graph real quick

Darya [45]

Answer:

(-3,-1)

Step-by-step explanation:

Its where the two intercect

3 0

1 year ago

The vertex of the parabola below is at the point (1,3), and the point (2,6) is

Inessa05 [86]

Answer:

B. y=3(x-1)2 + 3

Step-by-step explanation:

Given that

vertex of the parabola is at the point (1,3)

let's verify, if the option B is the correct equation of the parabola.

$y=3(x-1)^2 + 3\\ \\y=3(x^2+1-2x) + 3\\\\y=3x^2+3-6x + 3\\\\y=3x^2-6x + 6....Eq1$

comparing to standard equationof parabola (standard quadratic equation), we get

$a=3, b=-6 and c=6$

to find the vertex we use formula for x- coordinate as $x=-b/2a$

$x=-(-6)/2(3)\\\\x=6/6\\x=1$

to find y put x=1 in the Eq1, we get

$y=3(1)^2-6(1)+6\\\\y=3-6+6\\\\y=3$

vertex =(x,y) = (1, 3)

thus vertex of the parabola from the equation y=3(x-1)2 + 3 is (1,3), thus verified

7 0

2 years ago

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

3 0

2 years ago