Answer:
There are 171 members in the club
Number of boys = 38
Number of girls = 133
Step-by-step explanation:
Let
x = total members of the club
Boys = 2/9x
if there are 95 more girls than boys
Girls = 2/9x + 95
how many girls are there in club?
Total members in the club = boys + girls
x = 2/9x + 2/9x + 95
x = 2+2/9x + 95
x = 4/9x + 95
x - 4/9x = 95
9x-4x/9 = 95
5/9x = 95
Divide both sides by 5/9
x = 95 ÷ 5/9
= 95 × 9/5
= 855/5
= 171
boys = 2/9x
= 2/9 * 171
= 342 / 9
= 38
Girls = 2/9x + 95
= 38 + 95
= 133
Total = 38 + 133
= 171
There are 171 members in the club
Number of boys = 38
Number of girls = 133
Answer: The correct option are B, C and D.
Explanation:
The law of sine states that,
Where A, B, C are interior angles of the triangle and a, b, c are sides opposite sides of these angles respectively as shown in below figure. Only AAS or SSA types problems can be solved by using Law of sine.
Since we need the combination of two sides and one angle or two angles and one side.
In option A, the two consecutive angles are known and a side which makes the second angle with base side is known, therefore the first angle is opposite to the given side, so the law of sine can be used for AAS problems.
Therefore, option A is incorrect.
In option B a side is known and two inclined angle on that line are known. But to use Law of sine we want the line and angle which in not inclined on that line, therefore the ASA problem can not be solved by Law of sine and the option B is correct.
In option C two sides and their inclined angle is known. But to use Law of sine we want the side and angle which in not inclined on that line, therefore the SAS problem can not be solved by Law of sine and the option C is correct.
In option D three sides are given but any angle is not given, therefore the SSS problem can not be solved by Law of sine and the option D is correct.
<span>V/7= 22
Multiply 7 on both sides
Final Answer: V = 154</span>
Answer:
Circumference(C) of the circle is given by:
where, r is the radius of the circle.
As per the statement:
A circular swimming pool has a radius of 15 ft.
⇒radius of the pool(r) = 15 ft
There is a path all around that pool that is three feet wide.
⇒radius of the outer edge of the path around the pool(r') = 15 +3 = 18 ft
Substitute these in the formula we have;
⇒
Therefore, the circumference of the outer edge of the path around the pool is, 113.04 ft
3 because it is a better Dona a toon