The equidistant point for all three, will be the "centroid" of their triangular locations
thus $\bf \textit{Centroid of a Triangle}
\begin{array}{llll}
Amy
\begin{array}{llll}
(2,3)\\
x_1,y_1
\end{array}\quad Brian
\begin{array}{llll}
(0,7)\\
x_2,y_2
\end{array}\quad Claire
\begin{array}{llll}
(-2,3)\\
x_3,y_3
\end{array}\\ \quad \\\\\\
\left(\cfrac{x_1+x_2+x_3}{3}\quad ,\cfrac{y_1+y_2+y_3}{3}\quad \right)
\end{array} 
$

6 0

2 years ago

Click this link to view O'NET's Skills section for Municipal Clerks Note that common skills are listed toward the top

Alika [10]

Writing, reading comprehension

3 0

2 years ago

Read 2 more answers

Is it proportional or nonproportional

azamat

4 is the proportion because 8 + 4 is 12 then keep adding 12 + 4 = 16 + 4 = 20 So that mean it is proportional I hope that helps.

6 0

2 years ago