Answer:
4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)
This is an oxidation-reduction (redox) reaction:
4 N-III - 20 e- → 4 NII
(oxidation)
10 O0 + 20 e- → 10 O-II
(reduction)
NH3 is a reducing agent, O2 is an oxidizing agent.
Explanation:
good luck
To solve this problem, we can simply calculate for the
dose by multiplying the volume of solution containing Selenium 75 and the
activity of the Selenium 75. That is:
dose = 4.1 mL * (45 μCi/mL)
dose = 184.5 μCi
A substance that produces hydrogen ions is an acid