All categories

2 years ago

10 Points mark brainly, The equation of the line in this graph is y = _ x + _ .

Mathematics

2 answers:

postnew [5]2 years ago

5 0

Y=3/2+3 I believe that’s the answer.

Brilliant_brown [7]2 years ago

3 0

Hello!

First of all, let's find the slope, which is the rise/run. We have the points (-4,-3) and (-2,0). To get the run there, we move to the left two units. We rise up three units as well. Therefore our slope is positive. We have rise/run, which is 3/2 as our slope.

Now, b is the y-intercept, or when our line intersects with the y-axis. We can see that it intersects at a y-value of 3.

We can write our equation below.

y=3/2x+3

I hope this helps!

You might be interested in

Point J (-4, -6) and point K (4, 4) are located on a coordinate grid. Which measurement is closest to the distance between point

shepuryov [24]

Answer:

The points are sqrt(164) or 2sqrt(41) units apart.

Explanation:

You didn't provide the options in your question. But to find the distance, you need to use the distance formula.

d=sqrt((y2-y1)^2 + (x2-x1)^2)

d is the distance, and (x1, y1) and (x2, y2) are the points.

Use point J (-4,-6) for (x1,y1) and point K (4,4) for (x2, y2).

d=sqrt((4-(-6))^2 + (4-(-4))^2)

=sqrt(10^2 + 8^2)

=sqrt(100+64)

=sqrt(164)=2sqrt(41)

You can compare this to the answer options and find the closest. Hope I could help! :)

3 0

2 years ago

Rewrite 5 times X + 5 x 8 in parenthesies

sveta [45]

Answer:

5(X+5x8)

Step-by-step explanation:

i hope this helpssss

5 0

2 years ago

Read 2 more answers

Sommer wants to buy a new car. She currently drives a car that gets 24 miles per gallon. She is contemplating buying a car that

frozen [14]

answer

$962.50

set up equation

first, we want to find out how many gallons of gas she'll save a year

x1 = gallons for old car

x2 = gallons for new car

gallons saved = x1 - x2 since she uses more gallons with the old car with a lower miles per gallon

then, find how much she saves on gas by multiply the price per gallon (3.85) by gallons saved

price saved = gallons saved * price

price saved = (x1 - x2) * 3.85

gallons with old car

to find the number of gallons, we divide the number of miles (15000) by miles per gallon (24 for the old car)

x1 = 15000 / 24

x1 = 625

gallons with new car

use the same process as with the old car, but with 40 miles per gallon instead

x2 = 15000 / 40

x2 = 375

plug in values

price saved = (x1 - x2) * 3.85

price saved = (625 - 375) * 3.85

price saved = 250 * 3.85

price saved = $962.50

3 0

2 years ago

The joint probability density function of X and Y is given by fX,Y (x, y) = ( 6 7 x 2 + xy 2 if 0 < x < 1, 0 < y < 2

fredd [130]

I'm going to assume the joint density function is

$f_{X,Y}(x,y)=\begin{cases}\frac67(x^2+\frac{xy}2\right)&\text{for }0$

a. In order for $f_{X,Y}$ to be a proper probability density function, the integral over its support must be 1.

$\displaystyle\int_0^2\int_0^1\frac67\left(x^2+\frac{xy}2\right)\,\mathrm dx\,\mathrm dy=\frac67\int_0^2\left(\frac13+\frac y4\right)\,\mathrm dy=1$

b. You get the marginal density $f_X$ by integrating the joint density over all possible values of $Y$ :

$f_X(x)=\displaystyle\int_0^2f_{X,Y}(x,y)\,\mathrm dy=\boxed{\begin{cases}\frac67(2x^2+x)&\text{for }0$

c. We have

$P(X>Y)=\displaystyle\int_0^1\int_0^xf_{X,Y}(x,y)\,\mathrm dy\,\mathrm dx=\int_0^1\frac{15}{14}x^3\,\mathrm dx=\boxed{\frac{15}{56}}$

d. We have

$\displaystyle P\left(X$

and by definition of conditional probability,

$P\left(Y>\dfrac12\mid X\frac12\text{ and }X$

$\displaystyle=\dfrac{28}5\int_{1/2}^2\int_0^{1/2}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy=\boxed{\frac{69}{80}}$

e. We can find the expectation of $X$ using the marginal distribution found earlier.

$E[X]=\displaystyle\int_0^1xf_X(x)\,\mathrm dx=\frac67\int_0^1(2x^2+x)\,\mathrm dx=\boxed{\frac57}$

f. This part is cut off, but if you're supposed to find the expectation of $Y$ , there are several ways to do so.

Compute the marginal density of $Y$ , then directly compute the expected value.

$f_Y(y)=\displaystyle\int_0^1f_{X,Y}(x,y)\,\mathrm dx=\begin{cases}\frac1{14}(4+3y)&\text{for }0$

$\implies E[Y]=\displaystyle\int_0^2yf_Y(y)\,\mathrm dy=\frac87$

Compute the conditional density of $Y$ given $X=x$ , then use the law of total expectation.

$f_{Y\mid X}(y\mid x)=\dfrac{f_{X,Y}(x,y)}{f_X(x)}=\begin{cases}\frac{2x+y}{4x+2}&\text{for }0$

The law of total expectation says

$E[Y]=E[E[Y\mid X]]$

We have

$E[Y\mid X=x]=\displaystyle\int_0^2yf_{Y\mid X}(y\mid x)\,\mathrm dy=\frac{6x+4}{6x+3}=1+\frac1{6x+3}$

$\implies E[Y\mid X]=1+\dfrac1{6X+3}$

This random variable is undefined only when $X=-\frac12$ which is outside the support of $f_X$ , so we have

$E[Y]=E\left[1+\dfrac1{6X+3}\right]=\displaystyle\int_0^1\left(1+\frac1{6x+3}\right)f_X(x)\,\mathrm dx=\frac87$

5 0

2 years ago

Solve in 10 seconds or less

FromTheMoon [43]

Answer:

1 and 7/8 is the difference between the greatest and least amounts of rainfall.

Step-by-step explanation:

3 0

2 years ago

10 Points mark brainly, The equation of the line in this graph is y = ___ x + ___ .

10 Points mark brainly, The equation of the line in this graph is y = _ x + _ .