Answer:
90% CI expects to capture u 90% of time
(a) This means 0.9 * 1000 = 900 intervals will capture u
(b) Here we treat CI as binomial random variable, having probability 0.9 for success
n = 1000
p = 0.9
For this case, applying normal approximation to binomial, we get:
mean = n*p= 900
variance = n*p*(1-p) = 90
std dev = 9.4868
We want to Find : P(890 <= X <= 910) = P( 889.5 < X < 910.5) (integer continuity correction)
We convert to standard normal form, Z ~ N(0,1) by z1 = (x1 - u )/s
so z1 = (889.5 - 900 )/9.4868 = -1.11
so z2 = (910.5 - 900 )/9.4868 = 1.11
P( 889.5 < X < 910.5) = P(z1 < Z < z2) = P( Z < 1.11) - P(Z < -1.11)
= 0.8665 - 0.1335
= 0.733
Well, if you subtract one you get -1=log4^x. base four on each side: 4(to the power of negative 1)=4(to the power of log base four) x. Four to the power of log base 4 cancels, and you're left with 4 to the power of -1=x. the negative exponent recipricates, so x=1/4. you're welcome.
I honestly have no clue but h(x)=g(x+2)-1
I just need points sry
Wouldn't you just count back 30 minutes from 10:08?
If you round up to 10:10, it's a little easier. Picture an analog clock in your head. Every big number is five minutes, and every two is ten minutes. If we put it back to the 12, that's ten minutes back. Twenty minutes earlier from that would be 9:40. Since we added two minutes to make it easier, we've got to subtract those two minutes. So, the starting time would be 9:38.
I hope this isn't too confusing.
